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Evaporation
I live in central Indiana, and we have experienced daytime temperatures
between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. |
Evaporation
"Keith Nuttle" wrote in message ... I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. One cubic inch = 0.00432900431 US gallons So, measure the drop in water level (in inches) after 24 hours and multiply the result by the area of your pond (in square inches) then by 0.00432900431 US gallons, and you'll have your answer. For instance, my pond is 4 feet by 12 feet. On a typical hot summer day, I lose anywhere from 0.25 inch, to 0.5 inch. Using the lower number, which is more typical for my pond, I get 48 in x 144 in x 0.25 in x 0.00432900431 US gallons = 7.4805 gallons per day. |
Evaporation
Our pond can lose an inch in a day, but we have two falls and two streams to
promote evaporation. It loses more like 1/4 to 1/2" per day if the pump is off. Both surface and circulation count. Jim -- ____________________________________________ See our pond at: home.bellsouth.net\p\pwp-jameshurley Ask me about Jog-A-Thon fundraiser (clears $120+ per child) at: jogathon.net "Keith Nuttle" wrote in message ... I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. |
Evaporation
"Keith Nuttle" wrote in message ... I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. One cubic inch = 0.00432900431 US gallons So, measure the drop in water level (in inches) after 24 hours and multiply the result by the area of your pond (in square inches) then by 0.00432900431 US gallons, and you'll have your answer. For instance, my pond is 4 feet by 12 feet. On a typical hot summer day, I lose anywhere from 0.25 inch, to 0.5 inch. Using the lower number, which is more typical for my pond, I get 48 in x 144 in x 0.25 in x 0.00432900431 US gallons = 7.4805 gallons per day. |
Evaporation
Our pond can lose an inch in a day, but we have two falls and two streams to
promote evaporation. It loses more like 1/4 to 1/2" per day if the pump is off. Both surface and circulation count. Jim -- ____________________________________________ See our pond at: home.bellsouth.net\p\pwp-jameshurley Ask me about Jog-A-Thon fundraiser (clears $120+ per child) at: jogathon.net "Keith Nuttle" wrote in message ... I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. |
Evaporation
Thanks for the information.
I am new to ponds and I was not sure if I had a leak in the pond or it was evaporation. My 120 sqft pond is in three pools. There are two sluices from the top to the middle and one from the middle to lower. Sluice is about 9 inches wide. The upper ones has about 1 inch of water flow through the sluices from the top pond and the middle has about 2 inches of water. I am loosing about 20 gallons per day so from what you say I may not have a serious leak. Jim and Phyllis Hurley wrote: Our pond can lose an inch in a day, but we have two falls and two streams to promote evaporation. It loses more like 1/4 to 1/2" per day if the pump is off. Both surface and circulation count. Jim |
Evaporation
Keith Nuttle wrote in message ...
I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. Google will reveal this to be a complex thermodynamic question which has been given much attention. One answer I have found is: "References: I work with an equipment for measuring Evaporation called Evaporimeter. We have found evaporation rates of water in 20 degrees Celsius to be around 40 g/m2/hr. That completely ignores humidity [or dewpoint], unfortunatly. That quoted rate works out to about very roughly 1/8 inch/hour at 68F. If you do not get a satisfactory answer here, google around for a good scientific answer, besides, "Couple of inches," or inchaso." -- Crashj |
Evaporation
Keith Nuttle wrote in message ...
I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. Google will reveal this to be a complex thermodynamic question which has been given much attention. One answer I have found is: "References: I work with an equipment for measuring Evaporation called Evaporimeter. We have found evaporation rates of water in 20 degrees Celsius to be around 40 g/m2/hr. That completely ignores humidity [or dewpoint], unfortunatly. That quoted rate works out to about very roughly 1/8 inch/hour at 68F. If you do not get a satisfactory answer here, google around for a good scientific answer, besides, "Couple of inches," or inchaso." -- Crashj |
Evaporation
There is a nomograph program located at
http://www.kcmmb.org/FAQ/faq-default.htm which is used for determining the evaporation rate from concrete to determine when protective measures need to be taken to prevent drying shrinkage cracks. The nomograph is a zip program which is downloaded and installed on your computer. The inputs are atmospheric temperature, relative humidity, concrete temperature (pond temperature) and wind velocity. The output is in pounds per square foot per hour. Using average high and low temperature, average humidity and wind velocity you could compute the 24 hour evaporation loss. A loss of 1 pound per square foot would translate to about 1 1/2 inches. -- RichToyBox http://www.geocities.com/richtoybox/pondintro.html "Keith Nuttle" wrote in message ... I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. |
Evaporation
Kieth,
There are some empirical ways to find out about your rate of evaporation. There is a sheet on it (that we wrote a few years ago). I forgot who has it now. Briefly, put a cut off milk jug in the pond on a solid base. Fill it to the same level as the pond. Let both sit. They face essentially the same evaporation rates. If the pond goes down at a markedly faster rate than the jug, you have a leak. In this experiment, both the jug and the pond need to be still. You can't have the pond running a lot of water over the falls, etc, increasing the evaporation of the pond. Let us know if you try it. Jim -- ____________________________________________ See our pond at: home.bellsouth.net\p\pwp-jameshurley Ask me about Jog-A-Thon fundraiser (clears $120+ per child) at: jogathon.net "Keith Nuttle" wrote in message ... I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. |
Evaporation
Kieth,
There are some empirical ways to find out about your rate of evaporation. There is a sheet on it (that we wrote a few years ago). I forgot who has it now. Briefly, put a cut off milk jug in the pond on a solid base. Fill it to the same level as the pond. Let both sit. They face essentially the same evaporation rates. If the pond goes down at a markedly faster rate than the jug, you have a leak. In this experiment, both the jug and the pond need to be still. You can't have the pond running a lot of water over the falls, etc, increasing the evaporation of the pond. Let us know if you try it. Jim -- ____________________________________________ See our pond at: home.bellsouth.net\p\pwp-jameshurley Ask me about Jog-A-Thon fundraiser (clears $120+ per child) at: jogathon.net "Keith Nuttle" wrote in message ... I live in central Indiana, and we have experienced daytime temperatures between 75 and 90 degrees with dew points of 55 to 65 degrees. My pond has about 120 square feet of surface area. Can someone give me an estimate, in gallons, of the evaporation during a day. |
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