On 12/4/02 3:55 AM, in article , "Oz"
wrote:

Gordon Couger writes

If the well was 300 feet deep and
was 300 gallons a minute and the friction loss was 30 feet of head you would
have to provide power to lift 300 gallons a minute 370 feet 300 feet out of
the ground 50 feet to overcome friction and 20 feet for the pivot. I leave
it to the next guy to calculate the power to live 300gpm 370 feet. It's late
and some one else can find the table or do the math.

Oooh, an exam question!

370' equivalent lift = 120 m
300gpm = 50 gps = 250 l/s = 250 kg/s

energy/per sec = power (w)

250 x 120 x 9.8 = 300,000 W = 300 kW say 400 HP.

feels about right ....


I don't have the math to disagree but that HP seems high, especially for
only 300 gpm. Typical set up in my area is 750 gpm., 30 psi at the top of
the pivot point, a static water level of say 150 feet. Add 15 feet of
elevation to get to the top of the pivot point. Most electric well motors
here are 60 or 75 horsepower.


Dean






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