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Old 28-01-2004, 05:44 PM
Ken Russell
 
Posts: n/a
Default Salt in a Nutshell

Hi Lee,

Notwithstanding the impeccable source, something has suffered in the
translation :-(

I think you will find that the second statement should read;
1 lb of salt in 100 gallons of water = 0.012%

--
Ken Russell

"Lee B." wrote in message
...
| The numbers are kinda rounded to keep it simple. By the time you
extrapolate
| the decimal from 1 gallon to 100 gallons, it goes up just a little bit.
| Read a bit further down in the message and the conversion factors are
| shown/proved (all in metric). I got this info from a trusted source who's
| much better at math than I am: it's a "cheat sheet" that allows you to do
| the math without having to access web-based calculators.
|
| Lee
|
| "Ken Russell" wrote in message
| u...
| One of your numbers is off by a factor of 10.
|
| If 1 lb. of salt in 1 gallon of water = 1% salinity
| Then this CANNOT be correct;
| 1 lb. of salt in 100 gallons of water = .12%
|
|
| Ken Russell
|
| "Lee B." wrote in message
| ...
| | For those that need to calculate the size of their pond using salt, or
| need
| | to figure out how much to add:
| |
| | Salt in a Nutshell
| |
| |
| |
| | 1 lb. of salt in 1 gallon of water = 1% salinity
| |
| | 1 lb. of salt in 100 gallons of water = .12%
| |
| | (These are "generally accepted" numbers; if you want to "proof" the
| numbers,
| | it goes like this: 1 lb. salt /100 gallons water (convert to metric)
=
| 454
| | grams of salt / 378.5 liters of water = 454 grams of salt / 378,500
| grams
| of
| | water = 0.001199 ppm, or 0.12%)
| |
| |
| |
| | If there is no salt reading in the pond:
| |
| | # salt x 12 / % salinity = gallons of water
| |
| | Example:
| |
| | 25 lbs salt x 12 = 300 / .3 (salinity) = 1000 gal.
| |
| |
| |
| | If there is an existing salt reading:
| |
| | R1 = Reading 1 (existing); R2 = Reading 2 (resultant)
| |
| | # salt x 12 / (R2-R1) salinity = gallons of water
| |
| | Example (Say the existing salt level was .15; after salt it was .3, so
| the
| | number we're looking for is .3 - .15 = .15):
| |
| | 50 lbs. salt x 12 = 600 / .15 = 4000 gallons
| |
| |
| |
| | To get # salt needed with known gallons:
| |
| | (desired % / 12) x gallons of water = # salt
| |
| | Example (If you want to achieve a .2% of salt in a 1500 gallon pond):
| |
| | .2/12 = .01666 x 1500 = 24.999 lbs. of salt (call it 25!)
| |
| |
| |
| | Note: If there are salt levels already in the pond, remember to
subtract
| R1
| | from R2 to get your final reading; if you want a final reading of .2,
| but
| | the initial reading is .05, then the actual number you're looking for
is
| .15
| | (not .2)
| |
| |
| |
| | I hope this helps.
| |
| |
| |
| | Lee
| |
| |
|
|
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