I am so severely math challenged! You all are brilliant for even
trying to explain all this to such as me. Just a comment ....(sigh)

Nedra
http://www.geocities.com/Heartland/Pines/4836
http://community.webshots.com/user/nedra118

"Ken Russell" wrote in message
...
The amount of salt dissolved in water is termed the salinity and is
measured
either as a per cent, in parts-per-thousand (ppt), or in parts-per-million
(ppm) (where 10 ppt = 1% = 10000 ppm). The more common parts-per-thousand
measurement is the weight of the salt in pounds per thousand pounds of
water
(about 125 gallons). Pond-keepers often talk about the pounds of salt per
hundred gallons of water. Since 100 gallons of pure water weighs about 800
pounds, one pound of salt per hundred gallons equates to a salinity of
1.25
ppt (0.125% or 1250 ppm). (1 ppt = 0.8 pounds per hundred gallons)

--
Ken Russell

wrote in message
k.net...
| You'd better check those calculations again. 1 lb salt in 1 gallon of
water
| is 10.71% salinity!!!!
|
| Dean Markley
|
| "Lee B." wrote in message
| ...
| For those that need to calculate the size of their pond using salt, or
| need
| to figure out how much to add:
|
| Salt in a Nutshell
|
|
|
| 1 lb. of salt in 1 gallon of water = 1% salinity
|
| 1 lb. of salt in 100 gallons of water = .12%
|
| (These are "generally accepted" numbers; if you want to "proof" the
| numbers,
| it goes like this: 1 lb. salt /100 gallons water (convert to metric)
=
| 454
| grams of salt / 378.5 liters of water = 454 grams of salt / 378,500
grams
| of
| water = 0.001199 ppm, or 0.12%)
|
|
|
| If there is no salt reading in the pond:
|
| # salt x 12 / % salinity = gallons of water
|
| Example:
|
| 25 lbs salt x 12 = 300 / .3 (salinity) = 1000 gal.
|
|
|
| If there is an existing salt reading:
|
| R1 = Reading 1 (existing); R2 = Reading 2 (resultant)
|
| # salt x 12 / (R2-R1) salinity = gallons of water
|
| Example (Say the existing salt level was .15; after salt it was .3, so
the
| number we're looking for is .3 - .15 = .15):
|
| 50 lbs. salt x 12 = 600 / .15 = 4000 gallons
|
|
|
| To get # salt needed with known gallons:
|
| (desired % / 12) x gallons of water = # salt
|
| Example (If you want to achieve a .2% of salt in a 1500 gallon pond):
|
| .2/12 = .01666 x 1500 = 24.999 lbs. of salt (call it 25!)
|
|
|
| Note: If there are salt levels already in the pond, remember to
subtract
| R1
| from R2 to get your final reading; if you want a final reading of .2,
but
| the initial reading is .05, then the actual number you're looking for
is
| .15
| (not .2)
|
|
|
| I hope this helps.
|
|
|
| Lee
|
|
|
|


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