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Old 12-02-2004, 11:26 PM
Lee B.
 
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Default Salt in a Nutshell

OK, for all those who took exception to my math, I had a typo: it's 1 lb. of
salt in *12* gallons of water = 1% salinity. I've corrected my data sheet.
The sample math calculations ARE, however, correct.

Sorry for the delay in responding: my husband was back in the hospital again
and I was otherwise occupied.

Lee

"Lee B." wrote in message
...
For those that need to calculate the size of their pond using salt, or

need
to figure out how much to add:

Salt in a Nutshell



1 lb. of salt in 1 gallon of water = 1% salinity

1 lb. of salt in 100 gallons of water = .12%

(These are "generally accepted" numbers; if you want to "proof" the

numbers,
it goes like this: 1 lb. salt /100 gallons water (convert to metric) =

454
grams of salt / 378.5 liters of water = 454 grams of salt / 378,500 grams

of
water = 0.001199 ppm, or 0.12%)



If there is no salt reading in the pond:

# salt x 12 / % salinity = gallons of water

Example:

25 lbs salt x 12 = 300 / .3 (salinity) = 1000 gal.



If there is an existing salt reading:

R1 = Reading 1 (existing); R2 = Reading 2 (resultant)

# salt x 12 / (R2-R1) salinity = gallons of water

Example (Say the existing salt level was .15; after salt it was .3, so the
number we're looking for is .3 - .15 = .15):

50 lbs. salt x 12 = 600 / .15 = 4000 gallons



To get # salt needed with known gallons:

(desired % / 12) x gallons of water = # salt

Example (If you want to achieve a .2% of salt in a 1500 gallon pond):

.2/12 = .01666 x 1500 = 24.999 lbs. of salt (call it 25!)



Note: If there are salt levels already in the pond, remember to subtract

R1
from R2 to get your final reading; if you want a final reading of .2, but
the initial reading is .05, then the actual number you're looking for is

..15
(not .2)



I hope this helps.



Lee