On 1/5/2005 6:25 PM US(ET), Peter H took fingers to keys, and typed the
following:

willshak wrote:

On 1/1/2005 5:10 PM US(ET), Rick took fingers to keys, and typed the
following:

A mixture of 50-1, how do I mix it? For one gallon or litre of gas
how much
oil?
Thanks for any help


To get the proper mixture of oil per gallon of gas, divide 128 (# of
ounces in a gallon) by ratio.
i.e. 128 / 40 = 3.2, so a 40:1 ratio needs 3.2 oz. of oil.
Other ratios:
25:1 = 5.1 oz per gallon.
50:1 = 2.5 oz per gal.


That will work in the States... but not all of us are American.

Peter H

I'm sorry. I can't do anything about that.

To get the proper mixture of oil per Imperial gallon of gas, divide 160
(# of Imperial ounces in an Imperial gallon) by ratio.
i.e. 160 / 40 = 4, so a 40:1 ratio needs 4 Imperial oz. of oil added to
an Imperial gallon.
Other Imperial gallon/ounce ratios:
25:1 = 6.4 Imperial oz per Imperial gallon.
50:1 = 3.2 Imperial oz per Imperial gallon.

To get the proper mixture of oil per Litre of gas, divide 100 (# of
centilitres in a litre) by ratio.
i.e. 100 / 40 = 2.5, so a 40:1 ratio needs 2.5 centilitres (25
millilitres) of oil added to a litre of gas.
Other Litre ratios:
25:1 = 4.0 centilitres (40 millilitres) per litre.
50:1 = 2.0 centilitres (50 millilitres) per litre

--
Bill