In article ,
"BAC" writes:
|
| Don't want to appear pedantic, but isn't the formula for kinetic energy 1/2
| mv2? So if v is the same for two projectiles, the energy will vary by half
| the mass ratio, hence in your example it would be 3.5 times not 14 times?
| Apologies if incorrect :-)

Whereas I have no objection to appearing pedantic - hell, I am
a professional pedant :-)

It is m(v^2)/2. So, the ratio is (m1(v^2)/2)/(m2(v^2)/2). Cancelling
common factors, one gets m1/m2. You also may have missed the fact
that a .177 pellet has 1/14th the mass of a .22 bullet - both the
type and calibre are different.


Regards,
Nick Maclaren.